Dear PTFS team,

I don't understand "a scaling factor of 1.2 from one N to the next" Should I multiply each GFlops/s for each N by that factor?

Kind regards

Hassan Rady

Why should you multiply a Gflop/s number with 1.2? Think about the purpose of this benchmarking experiment.

This is just the usual way we set the problem size in order to get equidistant points on a logarithmic x axis. Length N = 10 * 1.2^{m}, with going from 0 to whatever is necessary to get to N=10^{8}.

Okay. Thanks!