Hello everyone,
in Slides 12 on page 13, why does x(j-1, k) not incur a load unlike the other accesses?
Thanks in advance.
The value x(j-1,k) has been accessed as x(j+1,k) two inner loop (i.e., j) iterations before. It will be still in the L1 cache with 100% probability, so it does not cause any traffic beyond the L1.